how do I start an app from script and send it multiple arguments

[RejectionMan]

hello all,

Im trying to create a batch script to start an application, but I cannot get all the parameters to the prog. This results in default settings which are not desired.

This is the line in question:

START "" %WINDIR%\NWQUOTA.EXE G: 300 75 95 % N Y 0 0

i need to start nwquota from the windows directory and send it the following arguments:

G: 300 75 95 % N Y 0 0

[RejectionMan]

obviously doing this in batch is going no where, any one know how to do it in Windows Scripting host? (WSH)

[InTheWayBoy]

I not sure, but wouldn't the correct synatx be:

START "%WINDIR%\NWQUOTA.EXE G: 300 75 95 % N Y 0 0"

Probably wrong, but just a thought!

UPDATE - Yeah I think I'm wrong...nevermind! However, upon looking at the site for NWQUOTA, I think you need to replace the "%" to "R" so it looks like this:

NWQUOTA.EXE G: 300 75 95 R N Y 0 0

That could be your problem possibly

[RejectionMan]

CMD interprets this:

START "%WINDIR%\NWQUOTA.EXE G: 300 75 95 % N Y 0 0"

as a string literal so it looks for the program: NWQUOTA.EXE G: 300 75 95 % N Y 0 0.exe

stupid thing.

if i run it from the run command or the command line this works no problems:

NWQUOTA.EXE G: 300 75 95 % N Y 0 0

replacing % with R breaks it (reverts to defaults)

I have seen someone work magic with quotetations that has made an app accept multiple params in the past but the best i can get it to do is reconize the first 2, even then windows borks it.

I might have to code that INI config that is soposed to be in the next ver, but i hate codeing.