GAME: MindTrap

Quote:

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Originally Posted by a d e p t

I think I even have your name up there in the list.

You didn't see it on page 1?

I'm editing the original post every time there is a score to be added.

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Which post?

Score

Quote:

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Originally Posted by a d e p t

Score

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I should have more than 4 points. Go back and check the whole thread...I am serious this time... :p

Quote:

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Originally Posted by Ya_know

I should have more than 4 points. Go back and check the whole thread...I am serious this time... :p

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How about you do it and I'll check only if I think you're full of it. https://forums.windrivers.com/images.../2005/03/1.gif

If it takes Sandy 3 hours to paint a fence, and it takes Claude 6 hours to complete the same job, how long would it take both of them working together at their normal paces to paint that same fence?


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2 hours.

In one hour, Sandy can paint 1/3, or 2/6, of the fence. In that same hour, Claude, lazy as he is, can paint 1/6 of the fence. So, in one hour, they can paint 3/6, or 1/2 of the fence together. After two hours, the fence is done.

Quote:

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Originally Posted by a d e p t

If it takes Sandy 3 hours to paint a fence, and it takes Claude 6 hours to complete the same job, how long would it take both of them working together at their normal paces to paint that same fence?

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2 hours. In one hour, Sandy can paint 1/3, or 2/6, of the fence. In that same hour, Claude, lazy as he is, can paint 1/6 of the fence. So, in one hour, they can paint 3/6, or 1/2 of the fence together. After two hours, the fence is done.

Quote:

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Originally Posted by Deity

2 hours. In one hour, Sandy can paint 1/3, or 2/6, of the fence. In that same hour, Claude, lazy as he is, can paint 1/6 of the fence. So, in one hour, they can paint 3/6, or 1/2 of the fence together. After two hours, the fence is done.

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Excellent.

That brings you back up to ... let me check ... I always had problems adding negative and positive integers...

-122! https://forums.windrivers.com/images.../2006/04/1.gif

Quote:

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Originally Posted by a d e p t

Excellent.

That brings you back up to ... let me check ... I always had problems adding negative and positive integers...

-122! https://forums.windrivers.com/images.../2006/04/1.gif

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Sweet. One way or another, I'm going to have a record score. :eek2:

Quote:

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Originally Posted by Deity

Sweet. One way or another, I'm going to have a record score. :eek2:

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LOL https://forums.windrivers.com/images.../2005/03/1.gif

Who's lame now, huh? https://forums.windrivers.com/images.../2005/02/1.gif

Bill and Ted were on a round trip using the same route both ways.

Bill drove the first 40 miles and then Ted drove the rest of the way.

On the way back, Bill was first at the wheel again, and then Ted drove the last 50 miles.

Which of the two drove longest, and how many more miles did he drive?


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Ted drove 20 miles farther than Bill.

x = Total distance one way
Bill's miles = 40 + (x - 50) = x -10
Ted's miles = (x - 40) + 50 = x + 10

Ted drove ten miles more than the total distance one way. Since Bill drove ten less, the total difference is 20.

Quote:

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Originally Posted by a d e p t

Bill and Ted were on a round trip using the same route both ways.

Bill drove the first 40 miles and then Ted drove the rest of the way.

On the way back, Bill was first at the wheel again, and then Ted drove the last 50 miles.

Which of the two drove longest, and how many more miles did he drive?

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Ted drove 20 miles farther than Bill.

x = Total distance one way
Bill's miles = 40 + (x - 50) = x -10
Ted's miles = (x - 40) + 50 = x + 10

Ted drove ten miles more than the total distance one way. Since Bill drove ten less, the total difference is 20.

Quote:

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Originally Posted by Deity

Ted drove 20 miles farther than Bill.

x = Total distance one way
Bill's miles = 40 + (x - 50) = x -10
Ted's miles = (x - 40) + 50 = x + 10

Ted drove ten miles more than the total distance one way. Since Bill drove ten less, the total difference is 20.

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3 more points to the alien. https://forums.windrivers.com/images.../2005/03/1.gif

There are 100 socks in a drawer. 25 pairs of socks are red, the others are blue.

In complete darkness, what would be the minimum number of socks you would have to draw out to make sure you had 2 socks of the same colour?

And what would be the minimum number of socks needed to ensure you had a specific colour?


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3 socks for two of the same color.

51 socks for two of a specific color.

Quote:

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Originally Posted by a d e p t

There are 100 socks in a drawer. 25 pairs of socks are red, the others are blue.

In complete darkness, what would be the minimum number of socks you would have to draw out to make sure you had 2 socks of the same colour?

And what would be the minimum number of socks needed to ensure you had a specific colour?

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3 socks for two of the same color.

51 socks for two of a specific color.

Although, I wonder how you know you got the color you wanted given you're in complete darkness.

Quote:

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Originally Posted by Deity

3 socks for two of the same color.

51 socks for two of a specific color.

Although, I wonder how you know you got the color you wanted given you're in complete darkness.

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3 points for the questions, and an extra for being a smarta$$. https://forums.windrivers.com/images.../2005/03/1.gif


Thank you for playing today and embarrassing all your little buddies with your superior skills, Deity. I'm pretty sure you made some cry again. https://forums.windrivers.com/images.../2006/04/1.gif