Doh! Correction. Second answer should be 52. If you draw all 50 of one color first, wanting the opposite, you will need two more to get a pair of the second color.Quote:
Originally Posted by Deity
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Doh! Correction. Second answer should be 52. If you draw all 50 of one color first, wanting the opposite, you will need two more to get a pair of the second color.Quote:
Originally Posted by Deity
I think I'll just go back to work and let some other people play. :sad:Quote:
Originally Posted by a d e p t
Enjoy! :thumbs:
But...Quote:
Originally Posted by Deity
Wait...
...dangit.
You're right.
I'll still give you the points for pointing out the error in my logic.
Thanks for embarrassing me too.
Now everybody is happy. https://forums.windrivers.com/images.../2005/03/1.gif
https://forums.windrivers.com/images.../2005/03/1.gif
I'm not crying, I got to eat lunch. :devil:Quote:
Originally Posted by Deity
Submitted by Wayward Clam:
An game show offers a contestant the opportunity to choose between doors number 1, 2, and 3. Behind one of these doors is a car, and the other two doors have goats behind them. Only the host knows which door had the car behind it.
The contestant is asked to choose one of the doors, but BEFORE what is behind the door is revealed, the host first says "Let's see what's behind one of these other doors!" and then reveals a goat.
Because the host knows where the car is, this is never a problem; he always has at least one door BESIDES the one the contestant picked that he could open to reveal a goat.
Then, before opening the contestant's chosen door, he always the participant the choice to either STAY with the door originally chosen, or to SWITCH to the other unopened door.
The question is, are the odds better by staying with the original choice, switching to the other unopened door, or are the odds the same? The more important part of the question is, WHY?
__________
He should SWITCH.
You have a 2 in 3 chance of winning if you SWITCH.
Because your original choice of door was 1/3 likely to win, and you have had NO information revealed that affects the odds, as it is ALWAYS possible for the host to reveal a goat, no matter what you picked.
This means that there is a 2/3 chance that the door you originally chose is WRONG, meaning there is a 2/3 chance that the remaining door is RIGHT.
He should switch. There is a 50 % chance the dorr he switches to is a car. His original door is only a 33% chance of being a carQuote:
Originally Posted by a d e p t
Wow.Quote:
Originally Posted by edball
That was a hard one. https://forums.windrivers.com/images.../2005/03/1.gif
3 points. :D
What do you expect, it was from Wayward Clam... :pQuote:
Originally Posted by a d e p t
What's in a song, but not in a tune?
What's in a star, but not in the moon.
What's in the sun, but gone in the night
Out of range, but still in sight?
__________
The letter S.
The letter SQuote:
Originally Posted by a d e p t
I'm telling. https://forums.windrivers.com/images.../2005/03/1.gifQuote:
Originally Posted by edball
Beware the mollusc's wrath genie boy. ;)Quote:
Originally Posted by edball
Well there you go.Quote:
Originally Posted by Deity
3 points. :)
Weedy Willie was getting too old to work the land alone so he decided to divide his cornfield between himself and his four sons in proportion to their five work rates.
He knew that Rastus, Wig, Twig and Swig together could plant a field of corn in five hours whereas Wig, Twig and Swig and himself together could manage the same task in six hours.
So Weedy divided his field into a two-digit square number of parts and kept just one part for himself. Now, Wig, Twig and Swig were identical triplets so each received the same whole number of parts.
How many parts did each son get?
__________
Rastus received 9 parts and the triplets each got 13 parts. Let the workrates of the triplets combined, Rastus and Willie be x, y, z, respectively. Then
5(x + y) = 6(x + z) and so y = (x + 6z)/5Since z has one part, we can let x = nz where n is a whole number. We then have y = (6 + n)z/5. The ratio of the work rates of x, y, z is now
n : (6 + n)/5 : 1
Let the total of parts be m, a two-digit square number. We then have n + (6 + n)/5 + 1 =m so that n = (5m - 11)/6. The only solutions are n=19, m=25 or n=39, m=49. Since n is the total number of parts the triplets receive only the value divisible by three applies (n=39).
Oh that was hard...another one from "The Clam" ?Quote:
Originally Posted by a d e p t