GAME: MindTrap

[Khazad]

Maybe I should beat_ya to it......

i'll wait for confirmation from the man who gives the points first, not gonna waste my time if there's no point.

[3fingersalute]

i'll wait for confirmation from the man who gives the points first, not gonna waste my time if there's no point.

I think he's left for the day!

[confus-ed]

A well deserved bonus point to you, sir.

Who-hoo-hoo .. at last !! - a point, one single point that's all I ever wanted (I think Adept just took pity on me though )

[3fingersalute]

(I think Adept just took pity on me though )

It was the Christmas story mate.............it touched all of us !!

[Stalemate]

I think he's left for the day!

I have?




No points for questions which are now listed as "RESOLVED". Sorry.

[3fingersalute]

I have?




No points for questions which are now listed as "RESOLVED". Sorry.

I figured it was a Friday, you probably knocked off early.

(If ya_know what I mean )

[Stalemate]

It's official: 1=2

And here is the proof...

(1) X = Y -Given
(2) X2 = XY -Multiply both sides by X
(3) X2 - Y2 = XY - Y2 -Subtract Y2 from both sides
(4) (X+Y)(X-Y) = Y(X-Y) -Factor both sides
(5) (X+Y) = Y -Cancel out common factors
(6) Y+Y = Y -Substitute in from line (1)
(7) 2Y = Y -Collect the Y's
(8) 2 = 1 -Divide both sides by Y


What is wrong with this?


__________
The error arises in lines (4) and (5).
Because X = Y, the common factor (X-Y) is equal to zero. Therefore by cancelling out the common factor, one is dividing both sides by zero, the results of which are undefined. The result of this calculation can therefore be seen to be a simple fallacy.

(1) X = Y Given
(2) X2 = XY Multiply both sides by X
(3) X2 - Y2 = XY - Y2 Subtract Y2 from both sides
(4) (X+Y)(X-Y) = Y(X-Y) Factoring both sides by (x-y), ie zero, is nonsensical
(5) (X+Y) = Y Dividing both sides by zero leads to undefined results
(6) Y+Y = Y Substitute in from line (1)
(7) 2Y = Y Collect the Y's
(8) 2 = 1 Divide both sides by Y

[Khazad]

step 2 x times x is not 2x

[RIOT]

It's official: 1=2

And here is the proof...

(1) X = Y -Given
(2) X2 = XY -Multiply both sides by X
(3) X2 - Y2 = XY - Y2 -Subtract Y2 from both sides
(4) (X+Y)(X-Y) = Y(X-Y) -Factor both sides
(5) (X+Y) = Y -Cancel out common factors
(6) Y+Y = Y -Substitute in from line (1)
(7) 2Y = Y -Collect the Y's
(8) 2 = 1 -Divide both sides by Y


What is wrong with this?

How did you get the "2" in "X2" on the second step?

If X = Y and you multiplied both sides by X, you would get X squared = ZY.

[3fingersalute]

It's official: 1=2

And here is the proof...

(1) X = Y -Given
(2) X2 = XY -Multiply both sides by X
(3) X2 - Y2 = XY - Y2 -Subtract Y2 from both sides
(4) (X+Y)(X-Y) = Y(X-Y) -Factor both sides
(5) (X+Y) = Y -Cancel out common factors
(6) Y+Y = Y -Substitute in from line (1)
(7) 2Y = Y -Collect the Y's
(8) 2 = 1 -Divide both sides by Y


What is wrong with this?

If x=y, then x-y would equal 0.
When you try to divide by 0 in the next step to factor out, it can't be done Dividing by zero is impossible!

[Stalemate]

If x=y, then x-y would equal 0.
When you try to divide by 0 in the next step to factor out, it can't be done Dividing by zero is impossible!

That's it, for 3.

[Stalemate]

At the local F1 race track, Eddie was testing the latest car.

During the eight test laps, he managed to average the first two laps at 100mph, the next two laps at 102mph, the next two laps at 140mph and the last two laps at 150mph.

What was his average speed for the entire 8 laps?



__________
119mph:
Set the track length to be a random number, e.g. 5 miles. Therefore the first two laps took 10 miles / 100 mph = 10 / 100 hours. Similarly, the second two laps took 10 / 102 hours, etc.

The total time taken for 40 miles is therefore, 10/100 + 10/102 + 10/140 + 10/150 hours. Therefore the average speed for the entire 8 laps is 40 / (10/100 + 10/102 + 10/140 + 10/150) = 119 mph. QED.

[3fingersalute]

At the local F1 race track, Eddie was testing the latest car.

During the eight test laps, he managed to average the first two laps at 100mph, the next two laps at 102mph, the next two laps at 140mph and the last two laps at 150mph.

What was his average speed for the entire 8 laps?

100+100+102+102+140+140+150+150 = 984
984/8 =

123 mph??

[Stalemate]

No.

[3fingersalute]

119.0476 mph

We need to find the time for each lap. If it is a one mile track:

2/100 = .02
2/102 = .0196
2/140 = .0143
2/150 = .0133

Then divide total miles by total time 8/0.0672 = 119.0476mph