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June 14th, 2001, 09:44 PM
#1
autorun an app on startup in dos 6.2?
I have a stinky old laptop with DOS 6.2 on it, I only have one program on there and I would like it to open automatically when I startup my computermachine. Do I make a batch file or something? anybody know?
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June 14th, 2001, 10:28 PM
#2
You just need to type
edit autoexec.bat
from the c:\> and add the name and path of the executable below whatever is already there. Then save, exit, and reboot.
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June 15th, 2001, 12:41 AM
#3
Registered User
if the executable is a batch file Dont forget to add - Call - before the statement, E.G.
Call 1.bat
This means that executing the batch file doesnt terminate the current one.
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June 25th, 2001, 05:08 AM
#4
Registered User
Originally posted by Gabriel:
<STRONG>if the executable is a batch file Dont forget to add - Call - before the statement, E.G.
Call 1.bat
This means that executing the batch file doesnt terminate the current one.</STRONG>
Or even better, copy and paste the contents of 1.bat in to autoexec.bat, as using the CALL function will leave autoexec.bat partially finished, possible leaving drivers or TSRs uninstalled... not a "must-do", but it simplifies things for newbies.
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